## College Algebra (11th Edition)

Published by Pearson

# Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 409: 42

#### Answer

See the picture below.

#### Work Step by Step

The parent function is $f(x)=(\frac{1}{3})^x$ (with red) the given function is $g(x)=(\frac{1}{3})^x+4$ (with blue). The parent function can be graphed by calculating a few coordinates and connecting them with a smooth curve: $f(-2)=(\frac{1}{3})^{-2}=9$ $f(-1)=(\frac{1}{3})^{-1}=3$ $f(0)=(\frac{1}{3})^0=1$ $f(1)=(\frac{1}{3})^1=\frac{1}{3}$ $f(2)=(\frac{1}{3})^2=\frac{1}{9}$ For every corresponding x-value the following equation is true: $f(x)+4=g(x)$ This means that the graph is translated 4 units up ($g(x)$ involves a vertical shift of 4). Every $f(x)$ value will be increased by 4. (Because the original $f(x)$ will be equal to $f(x)+4$ with the same x-value. For example if $f(0)=1$ in the original $f(x)$, this will be translated as $f(0)+4=1+4=5$. We can see that here, the $g(x)$ is greater than $f(x)$ for every corresponding x-value by 4.)

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