College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 409: 12

Answer

$32$

Work Step by Step

$$g(x)=\left(\frac14\right)^x$$ Substitute $x=-\dfrac52$: $$g(x)=\left(\frac14\right)^{-\dfrac52}=$$ $$=(4)^\dfrac52=\sqrt{4}^5=2^5=32$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.