## College Algebra (11th Edition)

Published by Pearson

# Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises: 22

#### Answer

See the picture below.

#### Work Step by Step

By calculating a few pairs and connecting the dots on the graph with a smooth curve, we graph the function. A few pairs: $f(-1)=\frac{5}{3}^{-1}=\frac{3}{5}=0.6$ $f(0)=\frac{5}{3}^0=1$ $f(1)=\frac{5}{3}^1=\frac{5}{3}\approx 1.67$ $f(2)=\frac{5}{3}^2=\frac{25}{9}\approx 2.77$

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