College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 409: 20

Answer

See the picture below.
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Work Step by Step

By calculating a few pairs and connecting the dots on the graph with a smooth curve, we graph the function. A few pairs: $f(-1)=\frac{1}{4}^{-1}=4$ $f(0)=\frac{1}{4}^0=1$ $f(1)=\frac{1}{4}^1=\frac{1}{4}=0.25$ $f(2)=\frac{1}{4}^2=\frac{1}{16}=0.0625$
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