Answer
See the picture below
Work Step by Step
By calculating a few pairs and connecting the dots on the graph with a smooth curve, we can graph both functions.
A few pairs from the function $f(x)=2^x$ (with red colour):
$f(0)=2^0=1$
$f(1)=2^1=2$
$f(2)=2^2=4$
$f(3)=2^3=8$
A few pairs from the function $f(x)=-2^{x+2}$ (with blue colour):
$f(-1)=-2^{-1+2}=2^{1}=2$
$f(0)=-2^{0+2}=2^2=4$
$f(1)=-2^{1+2}=2^3=8$
$f(2)=-2^{2+2}=2^4=16$
As we can see the graph is translated 2 units left and then is reflected across the x-axis.
