College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises: 21

Answer

See the picture below.
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Work Step by Step

By calculating a few pairs and connecting the dots on the graph with a smooth curve, we graph the function. A few pairs: $f(-1)=\frac{3}{2}^{-1}=\frac{2}{3}\approx 0.67$ $f(0)=\frac{3}{2}^0=1$ $f(1)=\frac{3}{2}^1=\frac{3}{2}=1.5$ $f(2)=\frac{3}{2}^2=\frac{9}{4}=2.25$
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