Answer
$6,-\frac{1}{4}$
Work Step by Step
$|4x^2-23x-6|=0$
$4x^2-23x-6=0$
$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-23)\pm\sqrt{(-23)^2-4(4)(-6)}}{2(4)}=\dfrac{23\pm25}{8}$
$x_1=\dfrac{23+25}{8}=6$
$x_2=\dfrac{23-25}{8}=-\dfrac{1}{4}$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 1 - Section 1.8 - Absolute Value Equations and Inequalities - 1.8 Exercises - Page 154: 73
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