College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.8 - Absolute Value Equations and Inequalities - 1.8 Exercises - Page 154: 41

Answer

$\left[ -101,-99 \right]$

Work Step by Step

Since for any $a\gt0$, $|x|\le a$ implies $-a\le x \le a$ then the solution to the given inequality, $ \left| 0.01x+1 \right|\le 0.01 ,$ is \begin{array}{l}\require{cancel} -0.01\le 0.01x+1\le 0.01 \\\\ 100(-0.01)\le 100(0.01x+1)\le 100(0.01) \\\\ -1\le x+100\le 1 \\\\ -1-100\le x+100-100\le 1-100 \\\\ -101\le x\le -99 .\end{array} Hence, the solution set is the interval $ \left[ -101,-99 \right] .$
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