Answer
$(-4,-1)$
Work Step by Step
Since for any $a\gt0$, $|x|\lt a$ implies $-a\lt x \lt a$ then the solution to the given inequality, $
\left| 2x+5 \right|\lt 3
,$ is
\begin{array}{l}\require{cancel}
-3\lt 2x+5\lt 3
\\\\
-3-5\lt 2x+5-5\lt 3-5
\\\\
-8\lt 2x\lt -2
\\\\
-\dfrac{8}{2}\lt \dfrac{2x}{2}\lt -\dfrac{2}{2}
\\\\
-4\lt x\lt -1
.\end{array}
Hence, the solution set is the interval $
(-4,-1)
.$
