## College Algebra (11th Edition)

$x=-\dfrac{5}{8}$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $|8x+5|=0 ,$ use the fact that $|x|=0$ implies $x=0.$ $\bf{\text{Solution Details:}}$ Since $|x|=0$ implies $x=0,$ the equation above is equivalent to \begin{array}{l}\require{cancel} 8x+5=0 .\end{array} Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} 8x=-5 \\\\ x=-\dfrac{5}{8} .\end{array}