College Algebra (11th Edition)

$\bf{\text{Solution Outline:}}$ Use the concepts of absolute value expressions to solve the given inequality, $|6-3x|\lt-11 .$ $\bf{\text{Solution Details:}}$ The absolute value of a number is the distance of the number from $0,$ and hence, is always a nonnegative number. In the same reason, for any $x$, the given absolute value expression at the left side is always a nonnegative number. This will never be $\text{ less than }$ the negative expression at the right. Hence, there is $\text{ no solution .}$