College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 679: 34

Answer

See below.

Work Step by Step

a) The nth term of an arithmetic sequence can be obtained by the following formula: $a_n=a_1+(n-1)d$, where $a_1$ is the first term and $d$ is the common difference. Hence here: $d=-3,n=25,a_1=80,a_{25}=80+(25-1)(-3)=80-72=8$ b) The sum of the first $n$ terms of an arithmetic sequence can be obtained by the following formula: $\frac{n(a_1+a_n)}{2},$ where $a_1$ is the first term, $a_n$ is the nth term and $n$ is the number of terms. Hence here the sum: $\frac{n(a_1+a_n)}{2}=\frac{25(80+8)}{2}=1100$
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