Answer
See below.
Work Step by Step
By the formula we learned in this chapter: $\sum_{i=1}^{40} (-2i+8)=\sum_{i=1}^{40} -2i+\sum_{i=1}^{40}8=-2\sum_{i=1}^{40} i+\sum_{i=1}^{40}8=-2\frac{40(40+1)}{2}+40\cdot8=-1640+320=-1320$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Review Exercises - Page 679: 14
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