## College Algebra (10th Edition)

Published by Pearson

# Chapter 9 - Review Exercises - Page 679: 22

See below.

#### Work Step by Step

An infinite geometric series converges if and only if $|r|\lt1$, where $r$ is the common ratio. If it converges, then the sum equals $\frac{a_1}{1-r}$ where $a_1$ is the first term. Here $|r|=|1/3|=1/3\lt1$, thus it converges, with $a_1=3$, thus the multiplier: $\frac{3}{1-1/3}=4.5$

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