Answer
See below.
Work Step by Step
An infinite geometric series converges if and only if $|r|\lt1$, where $r$ is the common ratio. If it converges, then the sum equals $\frac{a_1}{1-r}$ where $a_1$ is the first term.
Here $|r|=|1/3|=1/3\lt1$, thus it converges, with $a_1=3$, thus the multiplier: $\frac{3}{1-1/3}=4.5$
