Answer
See below.
Work Step by Step
The difference between two terms with an index difference of $8$ is $8$, thus $d=8/8=1$. Thus $a_1=a_{10}-(10-1)d=0-9(1)=-9$.
The nth term of an arithmetic sequence can be obtained by the following formula: $a_n=a_1+(n-1)d$, where $a_1$ is the first term and $d$ is the common difference.
Hence here: $d=1,a_1=-9,a_{n}=-9+(n-1)(1)=-10+n$
