College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 679: 13

Answer

See below.

Work Step by Step

By the formula we learned in this chapter: $\sum_{i=1}^{30} (i^2+2)=\sum_{i=1}^{30} i^2+\sum_{i=1}^{30}2=\frac{30(30+1)(2(30)+1)}{6}+30\cdot2=9455+60=9515$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.