College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 679: 29

Answer

See below.

Work Step by Step

${n \choose k}=\frac{n!}{k!(n-k)!}$ Hence here: ${5\choose2}=\frac{5!}{2!(5-2)!}=10$
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