Answer
$b=4$
Work Step by Step
We know that if $a^x=y$, then $\log_a y=x$ and vice versa.
Hence here $b^2=16\\b=\sqrt{16}=\pm4$
But $b$ must be positive for the logarithm, thus $b=4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Test - Page 502: 6
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