College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Test - Page 502: 15

Answer

$91$

Work Step by Step

We know that if $a^x=y$, then $\log_a y=x$ and vice versa. Hence here $10^2=x+9\\100=x+9\\x=91$
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