Answer
$\log_2(4)+3\log(x)-\log(x-6)-\log(x+3)$
Work Step by Step
$\log_2\left(\dfrac{4x^3}{x^2-3x-18}\right)$
$\log_2\left(\dfrac{4\cdot x^3}{(x-6)(x+3)}\right)$
$\log_2\left(4\cdot x^3\cdot\dfrac{1}{(x-6)}\cdot\dfrac{1}{(x+3)}\right)$
$\log_2\left(4\cdot x^3\div(x-6)\div(x+3)\right)$
$\log_2(4)+\log(x^3)-\log(x-6)-\log(x+3)$
$\log_2(4)+3\log(x)-\log(x-6)-\log(x+3)$
