College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Test - Page 502: 16

Answer

$x=-\ln2$

Work Step by Step

$8-2e^{-x}=4\\4=2e^{-x}\\2=e^{-x}\\\ln2=-x\\x=-\ln2$
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