College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding: 8


$x=\frac{10}{3} \approx 3.333$

Work Step by Step

RECALL: $\log_a{x} = y \longrightarrow a^y=x$ Use the rule above to obtain: $\log_3{(3x-1)} = 2 \\\longrightarrow 3^2=3x-1 \\9=3x-1 \\9+1=3x \\10=3x \\\frac{10}{3} = x \\x=\frac{10}{3} \approx 3.333$
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