College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 465: 13

Answer

$x=\dfrac{1}{3}$

Work Step by Step

Recall: (1) $n\log_a{x}=\log_a{x^n}$ (2) $\log_a{x}=\log_a{y}\longrightarrow x=y$ (3) $a^m=b^m\longrightarrow a=b$ The gievn equation is equivalent to: $$3\log_2{x}=-1\cdot \log_2{27}$$ Thus, using rule (1) above gives: $$\log_2{x^3}=\log_2{27^{-1}}$$ Using rule (2) above gives: \begin{align*} x^3&=27^{-1}\\ x^3&=\frac{1}{27^1}\\ x^3&=\frac{1}{27}\\ x^3&=\left(\frac{1}{3}\right)^3 \end{align*} Use rule (3) above to obtain: $$x=\dfrac{1}{3}$$
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