College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 465: 56

Answer

$\displaystyle \{\frac{3}{\ln\pi-1}\}$ or $\{20.728\}$

Work Step by Step

... Apply $\ln$(...) to both sides and isolate x $\ln e^{x+3}=\ln\pi^{x}$ $ x+3=x\ln\pi$ $3=x\ln\pi-x$ $3=x(\ln\pi-1)$ $x=\displaystyle \frac{3}{\ln\pi-1}\approx 20.728$ The solution set is $\displaystyle \{\frac{3}{\ln\pi-1}\}$ or $\{20.728\}$
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