College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 465: 47

Answer

$\displaystyle \{\frac{3-\log_{2}5}{3}\}$ or $\{0.226\}$

Work Step by Step

... Divide with 5 $2^{3x}=\displaystyle \frac{8}{5} \quad $... Apply $\log_{2}$(...) to both sides ... LHS: $\log_{2}2^{3x}=3x\log_{2}2=3x$ ... RHS: $\displaystyle \log_{2}\frac{8}{5}=\log_{2}8-\log_{2}5=\log_{2}2^{3}-\log_{2}5=3-\log_{2}5$ $3x=3-\log_{2}5$ $x=\displaystyle \frac{3-\log_{2}5}{3}\approx 0.226$ Solution set: $\displaystyle \{\frac{3-\log_{2}5}{3}\}$ or $\{0.226\}$
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