College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 465: 42



Work Step by Step

Write $25$ as $5^2$ to obtain: $5^{-x} = 5^2$ Use the rule $a^m=a^n\longrightarrow m=n$ to obtain: $-x=2 \\-1(-x)=-1(2) \\x=-2$ Thus, the solution is $x=-2$.
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