Answer
$y=Ce^{-2x}$
Work Step by Step
Subtract $\ln{C}$ on both sides:
$\ln{y} - \ln{C}=-2x$
RECALL:
For positive real numbers M and N:
$\ln{M} - \ln{N} = \ln{\left(\dfrac{M}{N}\right)}$
Use the rule above to obtain:
$\ln{\left(\dfrac{y}{C}\right)}=-2x$
RECALL:
$\ln{M}= y \longrightarrow e^y=M$
Use the rule above to obtain:
$e^{-2x}=\dfrac{y}{C}$
Multiply by $C$ on both sides of the equation to obtain:
$C \cdot e^{-2x} = C \cdot \dfrac{y}{C}
\\Ce^{-2x} = y
\\y=Ce^{-2x}$
