## College Algebra (10th Edition)

The given function is equivalent to: $y=\dfrac{\log{(x-2)}}{\log{(x+2)}}$ Refer to the image below for the graph.
RECALL: The change-of-base formula for logarithms: $\log_a{b}=\dfrac{\log{b}}{\log{a}}$ Thus, the given function is equivalent to: $y=\dfrac{\log{(x-2)}}{\log{(x+2)}}$ (refer to the attached image in the answer part above)