Answer
$y=Cx(x+1)$
Work Step by Step
RECALL:
For positive real numbers M and N:
(1) $\ln{M} = \ln{N} \longrightarrow M=N$
(2) Product Rule: $\ln{M} + \ln{N} = \ln{(MN)}$
(3) Quotient Rule: $\ln{M} - \ln{N} = \ln{\left(\dfrac{M}{N}\right)}$
(4) Power Rule: $r\cdot ln {M} = \ln{(M^r)}$
Apply the Product Rule to the first two terms on the right side of the equation to obtain:
$\ln{y}=\ln{x} + \ln{(x+1)}+\ln{C}
\\\ln{y} = \ln{\left[x(x+1)\right]} +\ln{C}$
Apply the Product Rule again to obtain:
$\ln{y}=\ln{x} + \ln{(x+1)}+\ln{C}
\\\ln{y} = \ln{\left[x(x+1)(C)\right]}
\\\ln{y} = \ln{\left[Cx(x+1)\right]}
$
Use rule (1) above to obtain:
$y=Cx(x+1)$
