College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 460: 106


See below.

Work Step by Step

We know that $\log_a x+\log_a y=log_a (x\cdot y)$, hence $f(AB)=\log{(AB)}=\log A+\log B=f(A)+f(B)$. Thus we proved what we had to.
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