College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 460: 110

Answer

See below.

Work Step by Step

We know that $log_a x^n=n\cdot log_a x$, hence $\log_a{\frac{1}{N}}=\log_a{(N^{-1})}=-\log_a(N)$
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