College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 460: 83

Answer

The given function is equivalent to: $y=\dfrac{\log{(x+1)}}{\log{(x-1)}}$ Refer to the image below for the graph.
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Work Step by Step

RECALL: The change-of-base formula for logarithms: $\log_a{b}=\dfrac{\log{b}}{\log{a}}$ Thus, the given function is equivalent to: $y=\dfrac{\log{(x+1)}}{\log{(x-1)}}$ (refer to the attached image in the answer part above)
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