Answer
The given function is equivalent to:
$y=\dfrac{\log{(x+1)}}{\log{(x-1)}}$
Refer to the image below for the graph.
Work Step by Step
RECALL:
The change-of-base formula for logarithms:
$\log_a{b}=\dfrac{\log{b}}{\log{a}}$
Thus, the given function is equivalent to:
$y=\dfrac{\log{(x+1)}}{\log{(x-1)}}$
(refer to the attached image in the answer part above)