College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Review Exercises - Page 500: 50

Answer

$P=41668.97$

Work Step by Step

$A(t)=P(1+\frac{r}{n})^{nt},$ $r=0.04, n=2, t=18, A(18)=85000,$ $A(18)=P(1+0.02)^{36}=85000,$ $P(1.02)^{36}=85000,$ $P=\frac{85000}{(1.02)^{36}}=41668.97$
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