Answer
See below.
Work Step by Step
a) By plugging in $d=4$ into the formula: $P=25(e)^{0.1\cdot4}=\approx37.3$
b) By plugging in $P=50$ into the formula: $50=25(e)^{0.1\cdot t}\\2=(e)^{0.1\cdot t}\\\ln{2}=0.1t\\t=10\ln{2}\approx6.93$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Review Exercises - Page 500: 46
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