Answer
$x=4.3011$
Work Step by Step
$5^x=3^{x+2},$
$x\log5=(x+2)\log3,$
$\frac{\log5}{\log3}=\frac{x+2}{x},$
$\frac{\log5}{\log3}=1+\frac{2}{x},$
$\frac{\log5}{\log3}-1=\frac{2}{x},$
$0.465=\frac{2}{x},$
$x=\frac{2}{0.465},$
$x=4.3011$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Review Exercises - Page 500: 37
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