Answer
$\frac{-16}{9}$
Work Step by Step
We know that $a^b=a^c\longrightarrow b=c$ if $a\ne1,a\ne-1$ (which applies here).
Hence here $8^{6+3x}=4\\(2^3)^{6+3x}=2^2\\2^{3(6+3x)}=2^2\\3(6+3x)=2\\18+9x=2\\9x=-16\\x=\frac{-16}{9}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Review Exercises - Page 500: 34
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
