College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Review Exercises - Page 500: 36

Answer

$\frac{1}{4}.$

Work Step by Step

We know that if $y=\log_a{b}$, then $a^y=b$. Hence here: $x^{-3}=64\\x^3=\frac{1}{64}\\x=\sqrt[3] \frac{1}{64}=\frac{1}{4}.$
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