College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Review Exercises - Page 499: 4

Answer

$f\circ g = 1-3x$ Domain: $\{x|\Re\}$ $g\circ f =7-3x$ Domain: $\{x|\Re \}$ c) $f\circ f =x$ Domain: $\{x|\Re \}$ d) $g\circ g = 9x+4$ Domain: $\{x|\Re\}$

Work Step by Step

$f\circ g = f(g(x)) = $ $2-(3x+1)=$ $2-3x-1=$ $1-3x$ Domain: $\{x|\Re\}$ $g\circ f = g(f(x)) =$ $3(2-x)+1=$ $6-3x+1=$ $7-3x$ Domain: $\{x|\Re \}$ c) $f\circ f = f(f(x))=$ $2-(2-x)=$ $2-2+x=$ $x$ Domain: $\{x|\Re \}$ d) $g\circ g = g(g(x))=$ $3(3x+1)+1=$ $9x+3+1=$ $9x+4$ Domain: $\{x|\Re\}$
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