Answer
a) $(f\circ g)(2)=e^4$
b) $(g\circ f)(-2)= 3e^{-2}-2$
c) $(f\circ f)(4)=e^{e^4}$
d) $(g\circ g)(-1)=-17$
Work Step by Step
a) $(f\circ g)(x)= f(g(x))=e^{3x-2}$
$f(g(2))=e^{3(2)-2}=e^4$
b) $(g\circ f)(x)= g(f(x))=3e^x-2$
$g(f(-2))=3e^{-2}-2$
c) $(f\circ f)(x)= f(f(x))=e^{e^x}$
$f(f(4))=e^{e^4}$
d) $(g\circ g)(x)= g(g(x))=3(3x-2)-2$
$g(g(-1))=3(3(-1)-2)-2=3(-5)-2=-15-2=-17$
