College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Review Exercises - Page 499: 21

Answer

$\log_3{u}+2\log_3{v}-\log_3{w}$

Work Step by Step

Recall: (1) $\log_a{(mn)}=\log_a{m} + \log_a{n}$ (2) $\log_a{\left(\frac{m}{n}\right)}=\log_a{m} - \log_a{n}$ (3) $\log_a{a^m}=m\log_a{m}$ Use rule (2) above to obtain: \begin{align*} \log_3{\left(\frac{uv^2}{w}\right)}-\log_3{w}&=\log_3{\left(uv^2\right)}-\log_3{w} \end{align*} Use rule (1) above to obtain: \begin{align*} \log_3{\left(uv^2\right)}-\log_3{w}&=\log_3{u}+\log_3{v^2}-\log_3{w} \end{align*} Use rule (3) above to obtain: \begin{align*} \log_3{u}+\log_3{v^2}-\log_3{w}&=\log_3{u}+2\log_3{v}-\log_3{w} \end{align*}
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