Answer
$x\gt\dfrac{2}{3}$
Work Step by Step
Recall:
In $\log_a{b}$, the value of $b$ is greater than $0$.
Thus, in $f(x)=\log{(3x-2)}$:
\begin{align*}
3x-2&\gt0\\
3x&\gt2\\
x&\gt\frac{2}{3}
\end{align*}
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