College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 5 - Section 5.5 - The Real Zeros of a Polynomial Function - 5.5 Assess Your Understanding: 42

Answer

$\pm 1;\pm 2;\pm 3;\pm 6;\pm 9;\pm 18;\pm \dfrac {1}{3};\pm \dfrac {2}{3}$

Work Step by Step

In a polinomial function like $f\left( x\right) =a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots a_{1}x+a_{0}$ If $p/q$, in lowest terms, is a rational zero of $f$, then p must be a factor of $a_0 $ and $q$ must be a factor of $a_n$. Here $f\left( x\right) =3x^{5}-x^{2}+2x+18\Rightarrow a_{n}=3;a_{0}=18 $ Factors of $a_0$ are $\pm 1,\pm 2,\pm 3,\pm6, \pm 9,\pm18$ Factors of $a_n$ are $\pm 1,\pm 3$ So the potential rational zeros are $\pm 1;\pm 2;\pm 3;\pm 6;\pm 9;\pm 18;\pm \dfrac {1}{3};\pm \dfrac {2}{3} $
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