## College Algebra (10th Edition)

$R=2$ $x+\dfrac {1}{3}$ is not a factor.
$f\left( x\right) =3x^{4}+x^{3}-3x+1=\left( x+\dfrac {1}{3}\right) q\left( x\right) +R$ $\Rightarrow f\left( -\dfrac {1}{3}\right) =2=R\neq 0$ Since $R\ne0$, $x+\dfrac {1}{3}$ is not a factor.