Answer
$0=R$
Since $R=0$, $x+2$ is a factor
Work Step by Step
$f\left( x\right) =4x^{4}-15x^{2}-4=\left( x-2\right) q\left( x\right) +R$
$\Rightarrow f\left( 2\right) =0=R$
Since $R=0$, $x+2$ is a factor
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