Answer
$R=0$
Since $R=0$, $x+3$ is a factor.
Work Step by Step
$f\left( x\right) =3x^{6}+82x^{3}+27=\left( x+3\right) q\left( x\right) +R$
$\Rightarrow f\left( -3\right) =3\times \left( -3\right) ^{6}+82\left( -3\right) ^{3}+27=0=R$
Since $R=0$, $x+3$ is a factor.