Chapter 5 - Section 5.5 - The Real Zeros of a Polynomial Function - 5.5 Assess Your Understanding - Page 387: 12

$161=R\ne0$ $x+3$ is not factor

Work Step by Step

$f\left( x\right) =-4x^{3}+5x^{2}+8=\left( x+3\right) q\left( x\right) +R$ $\Rightarrow f\left( -3\right) =161=R\ne0$ Since $f\left( -3\right) =R\neq 0$, $x+3$ is not factor

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