Answer
$\frac{3x^2+3x+1}{(3x+2)(x+1)}$
Work Step by Step
$\frac{1}{3x+2}+\frac{x}{x+1}=\frac{x+1}{(3x+2)(x+1)}+\frac{x(3x+2)}{(3x+2)(x+1)}=\frac{x+1+x(3x+2)}{(3x+2)(x+1)}=\frac{x+1+3x^2+2x}{(3x+2)(x+1)}=\frac{3x^2+3x+1}{(3x+2)(x+1)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 41
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