Answer
$\frac{4x-10}{(x+3)(x-3)}$
Work Step by Step
$\frac{2}{x^2-9}+\frac{4}{x+3}=\frac{2}{(x+3)(x-3)}+\frac{4(x-3)}{(x+3)(x-3)}=\frac{2+4(x-3)}{(x+3)(x-3)}=\frac{2+4x-12}{(x+3)(x-3)}=\frac{4x-10}{(x+3)(x-3)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 44
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