Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 11


All the real numbers except $x=-2$ and $x=-4$.

Work Step by Step

$\frac{x^2-5x+6}{x^2+6x+8}$ The denominator can not be equal to zero: $x^2+6x+8\ne0$ $x^2+4x+2x+8\ne0$ $x(x+4)+2(x+4)\ne0$ $(x+2)(x+4)\ne0$ $x\ne-2$ and $x\ne-4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.