## Algebra and Trigonometry 10th Edition

$\frac{1}{5x-10}$
$\frac{5}{x-1}.\frac{x-1}{25(x-2)}=\frac{5(x-1)}{(x-1)(25)(x-2)}$ Eliminate (x-1) in both numerator and denominator: $\frac{5}{(25)(x-2)}=\frac{5}{5(5)(x-2)}=\frac{1}{5(x-2)}=\frac{1}{5x-10}$